『「対話と決断」で成果を生む話し合いの作法』を読んだ。
「他人の靴を履く」という表現を知った。
こういう書籍を読むのはひさしぶりな気がする。
Apple Magic Trackpad を買った。届いたら書く。
- 分割 (第七回 アルゴリズム実技検定:M問題)
https://atcoder.jp/contests/past202107-open/tasks/past202107_m
- https://atcoder.jp/contests/past202107-open/submissions/44916109
- 解説 AC
- パッと見では最小費用流にさえ見えない……
- 二択にして容量 1 の最小費用流に落とし込むのはよくある形なのかもしれない……
- 辺の貼り方だけ整理できれば後は既存コードを貼るだけなので気づくことができれば簡単な問題なのかも……
use proconio::input; fn add_edge(edges: &mut [Vec<(usize, i64, i64, usize)>], u: usize, v: usize, cap: i64, cost: i64) { let index_u = edges[u].len(); let index_v = edges[v].len(); edges[u].push((v, cap, cost, index_v)); edges[v].push((u, 0, -cost, index_u)); } fn bellman_ford( edges: &[Vec<(usize, i64, i64, usize)>], s: usize, ) -> (Vec<i64>, Vec<usize>, Vec<usize>) { let inf = 1_i64 << 60; let mut dist = vec![inf; edges.len()]; dist[s] = 0; let mut prev_vert = vec![0_usize; edges.len()]; let mut prev_edge = vec![0_usize; edges.len()]; loop { let mut update = false; for v in 0..edges.len() { if dist[v] == inf { continue; } for (i, (u, cap, cost, _)) in edges[v].iter().copied().enumerate() { if cap > 0 && dist[u] > dist[v] + cost { dist[u] = dist[v] + cost; prev_vert[u] = v; prev_edge[u] = i; update = true; } } } if !update { break; } } (dist, prev_vert, prev_edge) } fn calc_min_cost_flow( edges: &mut [Vec<(usize, i64, i64, usize)>], s: usize, t: usize, mut capital_f: i64, ) -> i64 { let inf = 1_i64 << 60; let mut min_cost = 0_i64; while capital_f > 0 { let (dist, prev_vert, prev_edge) = bellman_ford(edges, s); if dist[t] == inf { return inf; } let mut v = t; let mut f = capital_f; while v != s { let u = prev_vert[v]; let i = prev_edge[v]; let c = edges[u][i].1; f = f.min(c); v = u; } v = t; while v != s { let u = prev_vert[v]; let i = prev_edge[v]; let j = edges[u][i].3; edges[u][i].1 -= f; edges[v][j].1 += f; v = u; } min_cost += f * dist[t]; capital_f -= f; } min_cost } fn main() { input! { n: usize, c: i64, a: [i64; n], } let start = n * 2; let end = n * 2 + 1; let offset_i = 0; let offset_j = n; let mut edges = vec![vec![]; n * 2 + 2]; for (i, a_i) in a.iter().copied().enumerate() { add_edge(&mut edges, start, offset_i + i, 1, 0); for j in i + 1..n { let a_j = a[j]; add_edge(&mut edges, offset_i + i, offset_j + j, 1, (a_i - a_j).abs()); } add_edge(&mut edges, offset_i + i, end, 1, c); } for j in 0..n { add_edge(&mut edges, offset_j + j, end, 1, 0); } let ans = calc_min_cost_flow(&mut edges, start, end, n as i64); println!("{}", ans); }
今日のコミット。